题解 | #整型数组合并#

#include<stdio.h>
#include<string.h>

int main()
{
    int count1;
    int count2;
    int a[1000];
    int b[1000];
    int c[1000];
    int d[1000];

    scanf("%d",&count1);
    for(int i = 0; i < count1; i++)
    {
       scanf("%d",&a[i]); 
       c[i] = a[i];
    }

    scanf("%d",&count2);
    for(int i = 0; i < count2; i++)
    {
       scanf("%d",&b[i]); 
       c[count1 + i ] = b[i];
    }

    
    for(int i = 0; i < count1 + count2; i++)
    {
        for(int j = i + 1; j < count1 + count2; j++)
        {

            if(c[i] > c[j])
            {
                int temp = c[i];
                c[i] = c[j];
                c[j] = temp;
            }
            

        }
        d[i] = c[i];
        if (i== 0)
            printf("%d",d[i]);
        else if (d[i-1] != c[i])
            printf("%d",d[i]);
            else
                continue;
    }

    return 0;

}

备注学习：该题难点在于如何数组中如何删掉重复数字。