题解 | #实现二叉树先序,中序和后序遍历#
实现二叉树先序,中序和后序遍历
https://www.nowcoder.com/practice/a9fec6c46a684ad5a3abd4e365a9d362
/**
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* };
*/
#include <vector>
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param root TreeNode类 the root of binary tree
* @return int整型vector<vector<>>
*/
vector<vector<int> > threeOrders(TreeNode* root) {
// write code here
vector<vector<int> > v;
vector<int> Tree1;
vector<int> Tree2;
vector<int> Tree3;
preOrder(Tree1,root);
inOrder(Tree2,root);
postOrder(Tree3,root);
v.push_back(Tree1);
v.push_back(Tree2);
v.push_back(Tree3);
return v;
}
void preOrder(vector<int> &Tree,TreeNode *root){
if(root == NULL){
return;
}
Tree.push_back(root->val);
preOrder(Tree, root->left);
preOrder(Tree, root->right);
}
void inOrder(vector<int> &Tree,TreeNode *root){
if(root == NULL){
return;
}
inOrder(Tree, root->left);
Tree.push_back(root->val);
inOrder(Tree, root->right);
}
void postOrder(vector<int> &Tree,TreeNode *root){
if(root == NULL){
return;
}
postOrder(Tree, root->left);
postOrder(Tree, root->right);
Tree.push_back(root->val);
}
};