题解 | #字符串合并处理#
字符串合并处理
https://www.nowcoder.com/practice/d3d8e23870584782b3dd48f26cb39c8f
while 1:
try:
s0 = input().split()
s1 = s0[0]
s2 = s0[1]
s = s1 + s2
s_new = ''
s_trans = ''
se = s[0:len(s):2]
so = s[1:len(s):2]
se = sorted(se)
so = sorted(so)
for i in range(len(se)):
if len(s) % 2 != 0 and i == len(se) - 1:
s_new = s_new + se[i]
break
s_new = s_new + se[i] + so[i]
for c in s_new:
if ord(c) in range(ord('0'), ord('9') + 1) or ord(c) in range(ord('a'), ord('f') + 1) or ord(c) in range(ord('A'), ord('F') + 1):
s_trans += hex(int((bin(int(c, 16))[2:].zfill(4))[::-1], 2)).upper()[2:]
else:
s_trans += c
print(s_trans)
except:
break


