题解 | #k-dis数对#
k-dis数对
https://www.nowcoder.com/practice/851207c8c6444085bca527f0567b356e
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param nums int整型一维数组 # @param k int整型 # @return int整型 # class Solution: def k_dis(self , nums: List[int], k: int) -> int: st=set() for c in nums: st.add(c) cnt=0 for c in st: if c+k in st: cnt=cnt+1 if c-k in st: cnt=cnt+1 return cnt//2