题解 | #简单密码#
简单密码
https://www.nowcoder.com/practice/7960b5038a2142a18e27e4c733855dac
str=input()
str1='abcdefghijklmnopqrstuvwxyz'
str2='ABCDEFGHIJKLMNOPQRSTUVWXYZ'
for element in str:
if element in str2:
element=element.lower()
if element=='z':
print('a', end="")
continue
print(chr(ord(element)+1),end="")
elif element in str1:
if element in 'abc':
element='2'
elif element in 'def':
element='3'
elif element in 'ghi':
element='4'
elif element in 'jkl':
element='5'
elif element in 'mno':
element='6'
elif element in 'pqrs':
element='7'
elif element in 'tuv':
element='8'
elif element in 'wxyz':
element='9'
print(element,end="")
else:
print(element,end="")
