题解 | #简单密码#

简单密码

https://www.nowcoder.com/practice/7960b5038a2142a18e27e4c733855dac

str=input()
str1='abcdefghijklmnopqrstuvwxyz'
str2='ABCDEFGHIJKLMNOPQRSTUVWXYZ'
for element in str:
    if element in str2:
        element=element.lower()
        if element=='z':
            print('a', end="")
            continue
        print(chr(ord(element)+1),end="")
    elif element in str1:
        if element in 'abc':
            element='2'
        elif element in 'def':
            element='3'
        elif element in 'ghi':
            element='4'
        elif element in 'jkl':
            element='5'
        elif element in 'mno':
            element='6'
        elif element in 'pqrs':
            element='7'
        elif element in 'tuv':
            element='8'
        elif element in 'wxyz':
            element='9'
        print(element,end="")
    else:
        print(element,end="")

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02-25 19:38
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