题解 | #Redraiment的走法#最长递增子序列默写
Redraiment的走法
https://www.nowcoder.com/practice/24e6243b9f0446b081b1d6d32f2aa3aa
import java.util.Scanner;
// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
// 注意 hasNext 和 hasNextLine 的区别
in.nextLine();
String ipt = in.nextLine();
String[] highs = ipt.split(" ");
int[] arr = new int[highs.length];
for(int i = 0;i < highs.length;i++){
arr[i] = Integer.parseInt(highs[i]);
}
/**
求最长递增子序列?
dp[i] 直到i为止的最长递增子序列
*/
int[] dp = new int[arr.length];
dp[0] = 1;
for(int i = 1; i < dp.length ; i++){
dp[i] = 1;
for(int j = 0; j < i ;j++){
if(arr[i] > arr[j]){
dp[i] = Math.max(dp[i],dp[j]+1);
}
}
}
int max = Integer.MIN_VALUE;
for(int i = 0;i< dp.length;i++)
max = Math.max(dp[i],max);
System.out.println(max);
}
}