题解 | #异常的邮件概率#
异常的邮件概率
https://www.nowcoder.com/practice/d6dd656483b545159d3aa89b4c26004e
select
date
,round(sum(if(type = 'no_completed',1,0))/count(*),3)
from email
where send_id not in
(
select
id
from user where is_blacklist = 1
)
and receive_id not in
(
select
id
from user where is_blacklist = 1
)
group by date
这里有
