题解 | #牛牛的线段#
牛牛的线段
https://www.nowcoder.com/practice/f72c56ed71664af082c921bf79861c85
#include <stdio.h>
#include <math.h>
int main() {
int a,b,c,d;
scanf("%d %d",&a,&b);
scanf("%d %d",&c,&d);
int result = pow(c-a,2)+pow(d-b,2);
printf("%d",result);
return 0;
}
