题解 | #兔子的序列#
兔子的序列
https://www.nowcoder.com/practice/55fc2ebad3fd444bbb1754ba1b259762
#include<math.h>
int main() {
int n, x;
scanf("%d\n", &n);
int a, max = 0;
for (int i = 0; i < n; i++) {
scanf("%d", &a);
x = sqrt(a);
if (a == pow(x, 2)) continue;
else {
if (a > max) max = a;
}
}
printf("%d", max);
return 0;
}
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