题解 | #树的子结构#
树的子结构
https://www.nowcoder.com/practice/6e196c44c7004d15b1610b9afca8bd88
import java.util.*; /** public class TreeNode { int val = 0; TreeNode left = null; TreeNode right = null; public TreeNode(int val) { this.val = val; } } */ public class Solution { public boolean HasSubtree(TreeNode root1,TreeNode root2) { if(root1 == null || root2 == null) return false; return Issame(root1, root2) || HasSubtree(root1.right, root2) || HasSubtree(root1.left, root2); } boolean Issame(TreeNode root1, TreeNode root2){ if(root2 == null) return true; //注意这两步的顺序 if(root1 == null) return false; if(root1.val != root2.val) return false; return Issame(root1.right, root2.right) && Issame(root1.left, root2.left); } }