题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
info = [int(i) for i in input().split()]
links = []
links.append(info[1])
for i in range(1, info[0]):
links.insert(links.index(info[2 * i + 1]) + 1, info[2 * i])
links.remove(info[-1])
print(" ".join([str(i) for i in links]))
