题解 | #时间转换#
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <stdio.h>
int main() {
int a = 0;
int s = 0;
int m = 0;
int h = 0;
scanf("%d", &a);
h = a/3600;
m = a/60 - 60*h;
s = a%60;
printf("%d %d %d", h, m, s);
return 0;
}
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