题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h>
float Price(int num)
{
if(num>60) return 0.2;
else return 0.1;
}
int main(void)
{
int n,num;
float price=0;
scanf("%d",&n);
for(int i=0;i<n;i++)
{
scanf("%d",&num);
price+=Price(num);
}
printf("%.1f\n",price);
return 0;
}
