题解 | #获取有奖金的员工相关信息。#

select
    t1.emp_no,
    t1.first_name,
    t1.last_name,
    t3.btype,
    t2.salary,
    round(
        case
            t3.btype
            when 1 then t2.salary * 0.1
            when 2 then t2.salary * 0.2
            else t2.salary * 0.3
        end,
        1
    ) as bonus
from
    employees t1
    join salaries t2 on t1.emp_no = t2.emp_no
    join emp_bonus t3 on t1.emp_no = t3.emp_no
where
    t2.to_date = '9999-01-01'
order by
    t1.emp_no