Simple implemented by python
number = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
Alphabet = [' ', ' ', 'abc', 'def', 'ghi', 'jkl', 'mno', 'pqrs', 'tuv', 'wxyz']
def alphabet_to_digital(inputstr):
result = []
for i in range(len(inputstr)):
for j in range(len(Alphabet)):
if inputstr[i] in Alphabet[j]:
result.append(number[j])
break
result_number = ''.join(result)
return result_number
def process_input(inputstr):
inputstr = inputstr.lower()
return inputstr
if __name__ == '__main__':
inputstr = process_input(input('please input the string:\n'))
print(f'the corresponding number is\n{alphabet_to_digital(inputstr)}') #Python##学习路径#
字节跳动公司福利 1371人发布