题解 | #反转链表#
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
import java.util.*;
/*
* public class ListNode {
* int val;
* ListNode next = null;
* public ListNode(int val) {
* this.val = val;
* }
* }
*/
/**
* 使用递归的方式解决
**/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @return ListNode类
*/
public ListNode ReverseList (ListNode head) {
// write code here
if(head == null){
return null;
}
ListNode cur = head;
while(cur.next != null){
cur = cur.next;
}
head = reverse(head);
head.next = null;
return cur;
}
public ListNode reverse(ListNode cur){
if(cur.next == null){
return cur;
}else{
ListNode next = reverse(cur.next);
next.next = cur;
return cur;
}
}
}
