题解 | #记负均正II#
记负均正II
https://www.nowcoder.com/practice/64f6f222499c4c94b338e588592b6a62
//简单的判断和统计，负数和非负数分开统计输出即可
#include <stdio.h>
int main()
{
int n=0,i=0,count=0,p=0,arr[50000]={0};
float num=0.0;
while(scanf("%d",&arr[i])!=EOF)
{
if(arr[i]<0)
{
count++;
}
if(arr[i]>=0)
{
p++;
num+=arr[i];
}
}
printf("%d\n%0.1f\n",count,num/p);
return 0;
}
