题解 | #数组中只出现一次的两个数字#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param nums int整型一维数组 
# @return int整型一维数组
#
class Solution:
    def FindNumsAppearOnce(self , nums: List[int]) -> List[int]:
        # write code here
        l = len(nums)
        a={}
        for i in range(l):
            if str(nums[i]) not in a.keys():
                a[str(nums[i])] = 1
            else:
                a[str(nums[i])]+=1
        
        result = []
        # print(a)
        for item in a:
            if a[item] == 1:
                result.append(int(item))
        
        result.sort(reverse=False)
        return result

哈希思路