题解 | #今天的刷题量(一)#
今天的刷题量(一)
https://www.nowcoder.com/practice/e18f56796ae94c3d885e61c8d57a950e
SELECT s.name, COUNT(*) AS cnt FROM submission AS sub JOIN subject AS s ON sub.subject_id = s.id WHERE DATE(sub.create_time) = CURDATE() GROUP BY s.name, s.id ORDER BY cnt DESC, s.id ASC;
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