题解 | #求解立方根#

//牛顿迭代法求一个数的n次方根
import java.util.Scanner;
public class Main{
    public static void main(String[] args){
        Scanner in = new Scanner(System.in);
        double number=in.nextDouble();
        double n=3.0;
        double episilon=1e-6;
        double guess=number/n;
        while(Math.abs(Math.pow(guess,n)-number)>episilon){
            guess=(1.0/n)*((n-1)*guess+number/Math.pow(guess,n-1));
        }
        System.out.printf("%.1f",guess);
        in.close();
    }
}