题解 | #牛牛的计划#
牛牛的计划
https://www.nowcoder.com/practice/cf956ceef9f84f7393a0b7284fdbf95a
#include <stdio.h> int main() { int x,y,z; int a,b,c; scanf("%d %d %d",&x,&y,&z); scanf("%d %d %d",&a,&b,&c); if((x<a)||(x==a&&(y<b||(y==b&&z<=c)))) printf("yes"); else printf("no"); return 0; }