题解 | #牛牛的计划#
牛牛的计划
https://www.nowcoder.com/practice/cf956ceef9f84f7393a0b7284fdbf95a
#include <stdio.h>
int main()
{
int x,y,z;
int a,b,c;
scanf("%d %d %d",&x,&y,&z);
scanf("%d %d %d",&a,&b,&c);
if((x<a)||(x==a&&(y<b||(y==b&&z<=c))))
printf("yes");
else
printf("no");
return 0;
}
