题解 | #小乐乐改数字#

#include<stdio.h>
#include<math.h>
int main()
{
    int n = 0;
    int sum = 0;
    int i = 0;
    scanf("%d", &n);
    while (n)
    {
        int a = n % 10;
        int ret = 0;
     
        if (0 == a % 2)
        {
            ret = 0;
        }
        else
        {
            ret = 1;
        }
        sum += (ret * pow(10, i));
        n /= 10;
        i++;
    }
    printf("%d", sum);
    return 0;
}