题解 | #矩阵乘法#

简洁明了的代码。

def fun():
    # 计算i行j列
    def get_i_j_value(i, j):
        ls_a， ls_b = a[i]， [b_row[j] for b_row in b]
        return sum([ls_a[ret_i] * ls_b[ret_i] for ret_i in range(len(ls_a))])
	  
    # 取得矩阵1和2的行列
    row1, col1, col2 = int(input().strip()), int(input().strip()), int(input().strip())
    # 推导式得到矩阵1和2
    a = [list(map(int, input().strip().split(" "))) for _ in range(row1)]
    b = [list(map(int, input().strip().split(" "))) for _ in range(col1)]
	
    # 遍历结果的第i,j位，求值
    res = [[get_i_j_value(i, j) for j in range(col2)] for i in range(row1)]
	
    # 打印结果
    for res_row in res:
        print(" ".join(list(map(str, res_row))))


fun()