题解 | #判断是不是完全二叉树#
判断是不是完全二叉树
https://www.nowcoder.com/practice/8daa4dff9e36409abba2adbe413d6fae
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param root TreeNode类
# @return bool布尔型
#
class Solution:
def isCompleteTree(self , root: TreeNode) -> bool:
# write code here
if not root:
return True
import collections
q = collections.deque()
q.append(root)
flag = False
while q:
node = q.popleft()
if not node:
flag = True
continue
else:
if flag:
return False
q.append(node.left)
q.append(node.right)
return True
利用队列的性质,如果在空节点后面还有节点就说明是非完全二叉树,设置一个flag去确定是否存在有空节点

