题解 | #牛群的树形结构重建#

牛群的树形结构重建

https://www.nowcoder.com/practice/bcabc826e1664316b42797aff48e5153

import java.util.*;

/*
 * public class TreeNode {
 *   int val = 0;
 *   TreeNode left = null;
 *   TreeNode right = null;
 *   public TreeNode(int val) {
 *     this.val = val;
 *   }
 * }
 */

public class Solution {
    /**
     * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
     *
     * 
     * @param inOrder int整型一维数组 
     * @param postOrder int整型一维数组 
     * @return TreeNode类
     */
    public TreeNode buildTree (int[] inOrder, int[] postOrder) {
        // write code here
        if(inOrder.length ==0){
            return null;
        }
        int rootVal = postOrder[postOrder.length -1];
        TreeNode result = new TreeNode(rootVal);
        int index = findRootIndex(inOrder,rootVal);
        TreeNode left = buildTree(Arrays.copyOfRange(inOrder,0,index),Arrays.copyOfRange(postOrder,0,index));
        TreeNode right = buildTree(Arrays.copyOfRange(inOrder, index + 1,inOrder.length),Arrays.copyOfRange(postOrder,index,postOrder.length-1));
        result.left = left;
        result.right = right;
        return result;     
    }

    public int findRootIndex(int[] arr,int rootVal){
        for(int i = 0; i < arr.length;i++){
            if(arr[i] == rootVal){
                return i;
            }
        }
        return -1;
    }
}

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