题解 | #牛牛学数列2#
牛牛学数列2
https://www.nowcoder.com/practice/fc72951f52984f3abd286d82eeffacba
#include <stdio.h>
int main() {
int n = 0, i = 0;
double sum = 0.0;
scanf("%d", &n);
//float类型变量仅精确到小数后六位，第六位可能不准确
//double类型精确到小数后15位，第六位是准确的
for (i = 1; i <= n; i++) {
sum += 1.0 / (double)i;
}
printf("%.6lf", sum);
return 0;
}
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