题解 | #小乐乐改数字#

#include <stdio.h>

int main() 
{
    long long n = 0; 
    int x,m=0;
    scanf("%lld",&n);
    for(long long i = 1;n>=1;i = i*10)
        {
             int t = n%10;
             if(t%2 == 1)
             x = 1;
            else
             x = 0;
             m = x*i+m;
             n = n / 10;
        }
    printf("%d",m);
    return 0;
}//123