题解 | #两个链表的第一个公共结点#

/*class ListNode {
 *     val: number
 *     next: ListNode | null
 *     constructor(val?: number, next?: ListNode | null) {
 *         this.val = (val===undefined ? 0 : val)
 *         this.next = (next===undefined ? null : next)
 *     }
 * }
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param pHead1 ListNode类 
 * @param pHead2 ListNode类 
 * @return ListNode类
 */
export function FindFirstCommonNode(pHead1: ListNode, pHead2: ListNode): ListNode {
    // write code here
    let cur1 = pHead1, cur2 = pHead2
    while(cur1 !== cur2) {
        cur1 = cur1 === null ? pHead2 : cur1.next
        cur2 = cur2 === null ? pHead1 : cur2.next
    }

    return cur1
}