题解 | #最长公共子序列(一)#
最长公共子序列(一)
https://www.nowcoder.com/practice/672ab5e541c64e4b9d11f66011059498
import java.util.Arrays; import java.util.Scanner; // 注意类名必须为 Main, 不要有任何 package xxx 信息 public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); final int N = in.nextInt(); final int M = in.nextInt(); String s1 = in.next(); String s2 = in.next(); int[][] maxLen = new int[N + 1][M + 1]; //maxLen[i + 1][j + 1]表示以s1[i][j]子串的最长公共子序列长度 for (int i = 0; i != N; ++i) { for (int j = 0; j != M; ++j) { int c1 = s1.charAt(i); int c2 = s2.charAt(j); if (c1 == c2) { maxLen[i + 1][j + 1] = maxLen[i][j] + 1; } else { maxLen[i + 1][j + 1] = Math.max(maxLen[i + 1][j], maxLen[i][j + 1]); } } } System.out.print(maxLen[N][M]); } }