题解 | #删除链表的倒数第n个节点#
删除链表的倒数第n个节点
https://www.nowcoder.com/practice/f95dcdafbde44b22a6d741baf71653f6
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* ListNode(int x) : val(x), next(nullptr) {}
* };
*/
#include <cstdlib>
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @param n int整型
* @return ListNode类
*/
ListNode* removeNthFromEnd(ListNode* head, int n) {
// write code here
int len = 0;
ListNode* p = head;
while (p != nullptr) {
len++;
p = p->next;
}
if (n == len) {
return head->next;
}
ListNode* q = head;
for (int i = 0; i < len - n - 1; i++) {
q = q->next;
}
ListNode* r = q->next;
q->next = q->next->next;
r->next = nullptr;
free(r);
return head;
}
};

