题解 | #删除链表的倒数第n个节点#
删除链表的倒数第n个节点
https://www.nowcoder.com/practice/f95dcdafbde44b22a6d741baf71653f6
/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ #include <cstdlib> class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @param n int整型 * @return ListNode类 */ ListNode* removeNthFromEnd(ListNode* head, int n) { // write code here int len = 0; ListNode* p = head; while (p != nullptr) { len++; p = p->next; } if (n == len) { return head->next; } ListNode* q = head; for (int i = 0; i < len - n - 1; i++) { q = q->next; } ListNode* r = q->next; q->next = q->next->next; r->next = nullptr; free(r); return head; } };