题解 | #子字符串频次#

const _searchStrIndexOf = (str, target) => {

  // 补全代码

  var nums = 0

  while(str.includes(target)) {

    let index = str.indexOf(target)

    str = str.slice(index + 1)

    nums ++

  }

  return nums

}

console.log(_searchStrIndexOf('abcabab','ab'));