题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h> int main() { int n=0; scanf("%d",&n); int arr[n]; float num=0.0; for(int i=1;i<=n;i++) { scanf("%d",&arr[i]); if(arr[i]>60) { num+=0.2; } else { num+=0.1; } } printf("%f",num); return 0; }