题解 | #质数因子#
质数因子
https://www.nowcoder.com/practice/196534628ca6490ebce2e336b47b3607
from math import sqrt
def judge(n):
for i in range(2,int(sqrt(n)+1)):
while n % i == 0:
print(i,end = ' ')
n = n // i
if n > 2:
print(n)
judge(int(input()))
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