题解 | #公共子串计算#
公共子串计算
https://www.nowcoder.com/practice/98dc82c094e043ccb7e0570e5342dd1b
a = input()
b = input()
r = []
if len(a) <= len(b):
a, b = a, b
else:
a, b = b, a
for i in range(len(a)+1):
for j in range(len(b)+1):
if a[i:j] in b:
if j-i > 0:
r.append(len(a[i:j]))
if len(r) == 0:
print('0')
else:
print(max(r))
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