题解 | #判断是不是二叉搜索树#
判断是不是二叉搜索树
https://www.nowcoder.com/practice/a69242b39baf45dea217815c7dedb52b
import java.util.*; /* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param root TreeNode类 * @return bool布尔型 */ public boolean isValidBST (TreeNode root) { // write code here if (root == null) { return true; } List<Integer> list = new ArrayList<>(); getTree(list, root); for (int i = 0; i < list.size() - 1; i++) { if (list.get(i) > list.get(i + 1)) { return false; } } return true; } public void getTree(List<Integer> list, TreeNode root) { if (root.left != null) { getTree(list, root.left); } list.add(root.val); if (root.right != null) { getTree(list, root.right); } } }