题解 | #字符串排序#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void async function () {
    // Write your code here
    let arr = [];
    let count = 0;
    while(line = await readline()) {
        count++;
        if(count == 1) {
            continue;
        }
        arr.push(line);
    }
	//关键在这里，字符串之间可以比较大小
    arr.sort((a, b) => {
        if(a > b) return 1;
        if(a < b) return -1;
        return 0;
    });
    for(let i = 0; i < arr.length; i++) {
        console.log(arr[i]);
    }
}()