题解 | #KiKi求质数个数#
KiKi求质数个数
https://www.nowcoder.com/practice/d3a404ee0f8d41f98bf4707035d91086
#include <stdio.h>
int main()
{
int i = 0, j = 0;
int n = 1;
int count = 0;
for (i = 100; i < 999; i++)
{
n = 1;
for (j = 2; j < i; j++)
{
if (i%j == 0)
{
n = 0;
}
}
if (n == 1)
{
count++;
}
}
printf("%d ", count);
return 0;
}
