题解 | #在字符串中找出连续最长的数字串#

import java.util.*;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        while (in.hasNextLine()) { // 注意 while 处理多个 case
            String line = in.nextLine();
            List<String> datas = new ArrayList<>();
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < line.length(); i++) {
                char c = line.charAt(i);
                if (c >= '0' && c <= '9') {
                    sb.append(c);
                } else {
                    if (sb.length() > 0) {
                        datas.add(sb.toString());
                        sb  = new StringBuilder();
                    }
                }
            }
            if (sb.length() > 0) {
                datas.add(sb.toString());
            }
            Collections.sort(datas, new Comparator<String>() {
                @Override
                public int compare(String o1, String o2) {
                    return Integer.compare(o2.length(), o1.length());
                }
            });
             if (datas.size()>0){
              int length = datas.get(0).length();
              sb= new StringBuilder();
              sb.append(datas.get(0));
              for (int i =1;i<datas.size();i++){
                  if (datas.get(i).length()==length){
                      sb.append(datas.get(i));
                  }else{
                      break;
                  }
              }
              System.out.println(sb.toString()+","+length);
          }
        }
    }
}