题解 | #输入n个整数，输出其中最小的k个#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void (async function () {
    // Write your code here
    var n = 0;
    var k = 0;
    var final = [];
    while ((line = await readline())) {
        let tokens = line.split(" ");
        if (n === 0 && tokens.length == 2) {
            n = tokens[0];
            k = tokens[1];
        } else {
            tokens.sort((a,b)=>(a-b));  // 按照从小到大的方式排序
            for(let i = 0; i<k;i++){
                final.push(tokens[i]);
            }
            console.log(final.join(" "));  // 将数组转为string，并用“ ”填充两个字符的中间值
        }
    }
})();