题解 | #人民币转换#

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(){
    char number[10][4] = {"零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"};
    char unit_num[24][4]={ "分", "角", "元","拾", "佰", "仟","万","拾", "佰", "仟", "亿","拾", "佰", "仟", "兆","拾", "佰", "仟", "京","拾", "佰", "仟"};
    long long int a;
    int b=0;
    int str_num[20]={0},index=0;
    scanf("%lld.%d",&a,&b);
    long long int tmp_a=a;
    int tmp_b=b;
    while(tmp_b>0){
        str_num[index]=tmp_b%10;
        index++;
        tmp_b/=10;
    }
    index=2;
    while(tmp_a>0){
        str_num[index]=tmp_a%10;
        index++;
        tmp_a/=10;
    }
    printf("人民币");
    for(int i=index-1;i>=2;i--){
        if(str_num[i]==0){//0遇到什么单位都不做输出,1遇到拾不输出
            int flag=0;
            while(i>=0&&str_num[i]==0) {
                if(flag==0&&(strcmp(unit_num[i], "万")==0
                ||strcmp(unit_num[i], "亿")==0
                ||strcmp(unit_num[i], "兆")==0
                ||strcmp(unit_num[i], "京")==0)){
                    flag=1;
                    printf("%s",unit_num[i]);
                }
                //中途经过这些单位要输出第一个
                i--;
            }
            if(i>=2){//防止吞掉个位数
                if(str_num[i]!=1||strcmp(unit_num[i], "拾")!=0)
                printf("零%s%s",number[str_num[i]],unit_num[i]);
                else
                printf("零拾");
            }else printf("元");
        }
        else if(str_num[i]==1&&strcmp(unit_num[i], "拾")==0)
            printf("拾");
        else
            printf("%s%s",number[str_num[i]],unit_num[i]);
    }
    if(b==0) printf("整");
    else{
    	if(str_num[1]!=0) 
        printf("%s%s",number[str_num[1]],unit_num[1]);
    	if(str_num[0]!=0) 
        printf("%s%s",number[str_num[0]],unit_num[0]);
	}
    return 0;
}