题解 | #输入n个整数，输出其中最小的k个#

import java.util.*;

public class Main {
    static ArrayList<Integer> list;

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        //读取输入
        while (in.hasNextInt()) {
            list = new ArrayList<>();
            int n = in.nextInt();
            int k = in.nextInt();
            for (int i = 0; i < n; i++) {
                list.add(in.nextInt());
            }
            //排序
            sort();
            //输出
            for (int i = 0; i < k; i++) {
                System.out.print(list.get(i) + " ");
            }
        }
    }

    private static void sort() {
        int size = list.size();
        for (int i = 0; i < size; i++) {
            for (int j = 0; j < size - i - 1; j++) {
                if (list.get(j) > list.get(j + 1)) {
                    int tmp = list.get(j + 1);
                    list.set(j + 1, list.get(j));
                    list.set(j, tmp);
                }
            }
        }
    }
}

解题思路:

1, 采用冒泡排序的方法进行排序;

2, 再进行输出即可