题解 | #子串计算#
子串计算
https://www.nowcoder.com/practice/bcad754c91a54994be31a239996e7c11
#include <iostream>
#include "map"
using namespace std;
int main() {
string s;
while (cin >> s) { // 注意 while 处理多个 case
// cout << a + b << endl;
map<string, int> myMap;
for (int i = 0; i <= s.size()-1; i++) {
for (int j = 1; i+j <= s.size(); j++) {
string temp = s.substr(i, j);
myMap[temp]++;
}
}
for (auto i = myMap.begin(); i != myMap.end(); i++) {
if (i->second > 1) cout << i->first << ' ' << i->second << endl;
}
}
}
// 64 位输出请用 printf("%lld")
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