题解 | #字符串变形#
字符串变形
https://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param s string字符串
# @param n int整型
# @return string字符串
#
class Solution:
def trans(self , s: str, n: int) -> str:
# write code here
def transtr(str):
if 97 <= ord(str) <= 122:
str = chr(ord(str) - 32)
elif 65 <= ord(str) <= 90:
str = chr(ord(str) + 32)
return str
ans = ''
flag = None
for i in range(1, len(s) + 1):
if s[-i]==' ':
if i == 1:
ans+=' '
flag = -i
continue
for j in s[-i + 1:flag]:
ans += transtr(j)
ans += ' '
flag = -i
if not s[0]==' ':
for j in s[0:flag]:
ans += transtr(j)
return ans