题解 | #打印日期#

#include<iostream>
#include<cstdio>

using namespace std;

int main() {
    int y, m, d, n;
    int a[2][12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31, 
					31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    int flag;//闰年的标志
    int sum;
    while (cin >> y >> n) {
        if ((y % 4 == 0 && y % 100 != 0) || y % 400 == 0)flag = 1;
        else flag = 0;
        sum = 0;
        m = 0;
        while ((sum + a[flag][m]) < n) {
            sum += a[flag][m];
            m++;
        }
        m++;
        d = n - sum;
        printf("%04d-%02d-%02d\n", y, m, d);
    }
    return 0;
}