题解 | #字符串归一化#
字符串归一化
https://www.nowcoder.com/practice/6d5e036defdf408681376a4a9d4930ff
import sys string=input() list1=[] result='' for i in string: if i not in list1: list1.append(i) list1.sort() j=0 while j<len(list1): result=result+list1[j]+str(string.count(list1[j])) j=j+1 print(result)