题解 | #日期累加#

#include <iostream>
using namespace std;

    int months[2][13]=
    {
        {0,31,28,31,30,31,30,31,31,30,31,30,31},
        {0,31,29,31,30,31,30,31,31,30,31,30,31}
    };
    int y,m,d,ad,index,n;

int main() {
    scanf("%d",&n);
    while(0<n--)
    {
        scanf("%d %d %d %d",&y,&m,&d,&ad);
        index=(y%400==0)||((y%4==0)&&(y%100!=0));
        while(0<ad--)
        {
            if(d+1<=months[index][m])
                ++d;
            else
            {
                if(m<12)
                    {++m;d=1;}
                else
                    {
                        ++y;m=d=1;
                        index=(y%400==0)||((y%4==0)&&(y%100!=0));

                    }
            }
        }
        printf("%d-%02d-%02d\n",y,m,d);
        
    }

    
}
// 64 位输出请用 printf("%lld")