题解 | #棋子翻转#
棋子翻转
https://www.nowcoder.com/practice/a8c89dc768c84ec29cbf9ca065e3f6b4
按照题意模拟即可
public class Solution { public int[][] flipChess (int[][] A, int[][] f) { int[] dx = {-1,0,1,0},dy = {0,1,0,-1}; int n = A.length; for(int[] arr : f){ int x = arr[0]-1,y = arr[1]-1; for(int i = 0; i < n; i++){ int cx = x + dx[i],cy = y + dy[i]; if(cx < 0 || cx >= n || cy < 0 || cy >= n){ continue; } A[cx][cy] = A[cx][cy]==1?0:1; } } return A; } }