题解 | #字符串加解密#
字符串加解密
https://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a
#include <string>
#include <iostream>
using namespace std;
string encode(string& s){
string res;
for(char c:s){
if(c>='a'&&c<='z'){
res+=(c-'a'+1)%26+'A';
}else if(c>='A'&&c<='Z'){
res+=(c-'A'+1)%26+'a';
}else if(c>='0'&&c<='9'){
res+=(c-'0'+1)%10+'0';
}
}
return res;
}
string decode(string& s){
string res;
for(char c:s){
if(c>='a'&&c<='z'){
if(c-'a'==0) res+='Z';
else res+=(c-'a'-1)%26+'A';
}else if(c>='A'&&c<='Z'){
if(c-'A'==0) res+='z';
else res+=(c-'A'-1)%26+'a';
}else{
if(c=='0') res+='9';
else res+=(c-'0'-1)%10+'0';
}
}
return res;
}
int main() {
string s1,s2;
getline(cin,s1);
getline(cin,s2);
cout<<encode(s1)<<endl;
cout<<decode(s2)<<endl;
}
得走出这种状态，不能一直困在那里面，哪不行就去提升哪，你一动不动那指定改变不了未来，动起来，积少成多才能越来越好