题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
a = input().split(' ') b = [] allnumber = int(a[0]) start = a[1] for i in range(allnumber-1): if i == 0: b.append(a[3+i]) b.append(a[2+i]) else: index = b.index(a[3+i*2]) b.insert(index+1,a[2+i*2]) delnumber = a[-1] b.remove(delnumber) for j in b: print(j,end=' ')