题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
a = input().split(' ')
b = []
allnumber = int(a[0])
start = a[1]
for i in range(allnumber-1):
if i == 0:
b.append(a[3+i])
b.append(a[2+i])
else:
index = b.index(a[3+i*2])
b.insert(index+1,a[2+i*2])
delnumber = a[-1]
b.remove(delnumber)
for j in b:
print(j,end=' ')
